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Concrete Breakout Failure due to Applied Forces

Posted by Tommy Carpenterabout 4 years ago
Concrete Breakout Failure due to Applied Forces

While I was trying to design a concrete foundation, I realized that the forces in the Y direction were being applied in the X direction according to Hilti. I have attached 3 PDF's. In PDF 1, It shows the reactions applied to the anchors. The only thing that I found strange is when I looked at pg.3 of the document it states that the concrete failed in the X direction. The vast majority of the force is applied in the Y direction. I ran another test to see what the unity would be if I didn't apply any force in the X and that can be seen in the Second PDF. This test shows that the anchors work fine. The final test I ran was to apply the force solely in the X direction and see what the unity would be. I found that the unity between PDF 1 and PDF 3 are the same even thought the forces in the X and Y directions are different. My question is why is it taking the resultant force and applying it solely in the X direction.

edge breakout,Resultant Forces

1 Reply
Posted by Emily about 4 years ago
Hilti Verified

Hi Tommy,

See this past Ask Hilti response which includes a resource that details how resultant shear loads are calculated in PROFIS Engineering/Anchor.

If you would like to discuss this further, please feel free to contact our Engineering Support team at hnatechnicalservices@hilti.com.

Best,
Emily