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Adhesive Anchor Critical Distance, CNa

Posted by Drew Mundtover 3 years ago
Adhesive Anchor Critical Distance, CNa

CNa=10*da*sqrt(tau uncr/1100). Bond strength, tau uncr is 2200 per ESR and as defined in the variables and the anchor diameter is 0.625 in. Based on this equation the critical distance should be 8.88 in however the report is computing 8.839 in. I have tested different temperature ranges and anchor diameters and the critical distance equation never matches up with the bond strength variable that is listed in the report. The bond strength value in the variables is being used to compute Nba and that values matches. Am I missing a factor when computing the critical distance equation?

bond strength,critical distance,cNa

1 Reply
Posted by Ashley Couronover 3 years ago
Hilti Verified

Hi Drew,
 
The value that PROFIS Engineering is calculating is correct per ACI-318-19 Eq.(17.6.5.1.2b). The equation is as follows: 10*(5/8)*(sqrt(2200/1100)) = 8.839. If you have any further questions regarding the PROFIS Engineering report, please reach out to hnatechnicalservices@hilti.com.
 
Regards,
Ashley